Question

a quadratic polynomial whose zeroes are 3/5 and -1/2​

Answer 1

here's yr answer
hope it helps
please mark it as brainliest

Answer 2

Given: The sum and product of zeroes are 3/5 and -1/2 respectively.

To find: The quadratic polynomial

Solution: Let the zeroes be a and b respectively.

a= 3/5

b= -1/2

Sum of zeroes

= a+b

$= \frac{3}{5} + ( - \frac{1}{2} )$

$= \frac{6 - 5}{10}$

$= \frac{1}{10}$

Product of zeroes

= a × b

$= \frac{3}{5} \times \frac{ - 1}{2}$

$= \frac{ - 3}{10}$

The expression for quadratic polynomial whose sum and product of zeroes are known can be written as:

${x}^{2} - (sum \: of \: roots)x + product \: of \: roots$

$= {x}^{2} - \frac{1}{10} x + ( - \frac{3}{10} )$

$= {x}^{2} - \frac{1}{10} x - \frac{3}{10}$

The quadratic polynomial whose sum and product of zeroes are 3/5 and -1/2 respectively is ${x}^{2} - \frac{1}{10} x - \frac{3}{10} .$