Question

a quadratic polynomial whose zeroes are -4 and -5 thrn the polynomial​

Answer 1

Answer:

here

$\alpha = - 4 \: and \: \beta = - 5 \\ sum \: of \: zeroes \: s \: = \alpha + \beta = - 4 - 5 = - 9 \\ product \: \: of \: zeroes \: p \: = \alpha \beta = ( - 4)( -5 ) = 20 \\ so \: required \: equation \: of \: polynomial \: is \\ f(x) = k( {x}^{2} - sx + p) \\ f(x) = k( {x}^{2} + 9x + 20) \: where \: k \: is \: non \: zero \: real \: number$

Answer 2

Answer:

x^2 - 9x + 20

Step-by-step explanation:

Formula for calculating Quadratic polynomial:-

     

                              x^2 + (Sum of zero's)x + (product of zero's)

Hence,                    x^2 + (-4 +(-5))x + (-4*-5)

                    Therefore,     x^2 - 9x + 20.

Now u got it. Boom!!!!