Question

a quadratic polynomial whose zeros are -3 and -4​

Answer 1

Answer:

$let \: \alpha = - 3 \: and \: \beta = - 4 \\ now \: required \: polynomial = > \\ {x}^{2} - ( \alpha + \beta ) + ( \alpha \beta ) \\ {x}^{2} - ( - 4 - 3) + ( - 4)( - 3) \\ = > {x}^{2} + 7 + 12$

Step-by-step explanation:

please mark as brainliest.

Answer 2

Solution -

The required Zeroes are -3 and 4 .

Sum of Zeroes -

=> -3 + 4

=> 1

Product Of Zeroes -

=> ( -3 )( 4 )

=> -12

Now , a quadratic polynomial can be written as -

x² - ( Sum of Zeroes ) x + ( Product Of Zeroes )

=> x² - ( 1 ) x - 12

=> x² - x - 12

Verification -

x² + x - 12

=> x² - 4x + 3x + 12

=> x ( x - 4 ) + 3 ( x - 4 )

=> ( x + 3 )( x - 4 )

Zeroes -

=> -3, 4

Hence Verified -

Additional Information -

In a Polynomial -

Sum of Zeroes = ( -b / a )

Product Of Zeroes = ( c / a )