a race track is the form of a ring whose inner circumference is 352 m and the outer circumference is 396 m find the width of the track and find the area of the track
Answers
here's ur answer...
for finding the width of the track we have first find the radius of both circles.
★ inner circumference=352m
therefore 2πr=352m
=> 2×22/7×r=352m
=> 44/7×r=352m
=> r=352/1×7/44
=> r=56m
VERIFICATION:-
CIRCUMFERENCE OF INNER CIRCLE=2πR
=2×22/7×56
=44×8
=352m
hence verified
thus the radius of inner circle is 56m.
★ outer circumference=396m
therefore 2πr=396m
=> 2×22/7×r=396m
=> 44/7×r=396m
=> r=396/1×7/44
=> r=63
VERIFICATION:-
CIRCUMFERENCE OF OUTER CIRCLE=πR²
=2×22/7×63
=44×9
=396m
hence verified
thus the radius of the outer circle is 63m
width of the track=63-56
=7m
★ area of inner circle=πr²
=22/7×56×56
=22×8×56
=9856m²
★ area of outer circle=πr²
=22/7×63×63
=22×9×63
=12474m²
hence area of the track=12474-9856
=2618m²
hope this helps..!
☺☺☺
Answer:
The width of the track is 7 m
Step-by-step explanation:
let the radius of inner track = r
let the radius of inner track = r2 pie r = 352
let the radius of inner track = r2 pie r = 352r = 56
let the radius of inner track = r2 pie r = 352r = 56let the radius of outer track = R
let the radius of inner track = r2 pie r = 352r = 56let the radius of outer track = R2 pie R = 396
let the radius of inner track = r2 pie r = 352r = 56let the radius of outer track = R2 pie R = 396R = 63
let the radius of inner track = r2 pie r = 352r = 56let the radius of outer track = R2 pie R = 396R = 63width of track = radius of outer track - radius of inner track
let the radius of inner track = r2 pie r = 352r = 56let the radius of outer track = R2 pie R = 396R = 63width of track = radius of outer track - radius of inner track=63 - 56
let the radius of inner track = r2 pie r = 352r = 56let the radius of outer track = R2 pie R = 396R = 63width of track = radius of outer track - radius of inner track=63 - 56= 7 m
mark as brainlest