Question

A racing car has a uniform acceleration of 4ms-2 what distance will it cover in 10- s after start

Answer 1

s=ut+ 1/2 f *t^2
u=0
s= 1/2 *4*10*10= 200 meter

Answer 2

$\textbf{\underline{\underline{According\:to\:the\:Question}}}$

${\boxed{\sf\:{Car\;starts\;from\;rest\;so\;initial\;velocity = 0 }}}$

★Given :-

u = 0

a = 4 m/s

t = 10 s

★To Find :-

s = ?

★Solution :-

${\boxed{\sf\:{Using\; second\; Equation\;of\;Motion}}}$

$\tt{\rightarrow s=ut+\dfrac{1}{2}at^{2}}$

$\tt{\rightarrow s=0\times 10+\dfrac{1}{2}\times 4\times (10)^{2}}$

$\tt{\rightarrow s=0+\dfrac{1}{2}\times 4\times (10)^{2}}$

$\tt{\rightarrow s=0+\dfrac{1}{2}\times 4\times 10\times 10}$

$\tt{\rightarrow s=\dfrac{1}{2}\times 4\times 100}$

= 200 m

★Hence we get :-

${\boxed{\sf\:{Car\;will\;cover\;distance\;of\;200 m \;in\; 10 s }}}$

$\boxed{\begin{minipage}{11 cm} Additional Information \\ \\ \ Distance = Speed\times Time \\ \\ Displacement=Velocity\times time \\ \\ Average\; Speed = \dfrac{Initial\:\:Speed+Final\:\:Speed}{2} \end{minipage}}$