A radioactive nuclide decays at such a ratethat after 96 min. only 1/8th of the originalamount remains. The value of half-life of thenuclide is:A 32 minB. 12 minC. 48 minD. 24 min
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Answer:
A. 32min
Explanation:
Initial no of radioactive nuclei = N
Amount of nuclei left after 96 min = N/8
No. of half lives(n) passed ;
1/2ⁿ = 1/8
∴ n=3
Value of a single half life = 96min/3 = 32min
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