A railway half ticket cost half the full fare and the reservation charge is the same on half ticket as on full ticket.one reserved first class ticket from Mumbai to delhi cost₹4150 while one full an one half resurved first class ticket cost₹ 6255. what is the basic first class full fare and what is the reservation charge.
Answers
Answered by
66
Hey!
It's a really simple question...
(Directly jump down if you are looking only for answer ; otherwise go through the answer :P)
Look...
Let's take the one full fare as "x" ,
So half fare would be "x/2"
And let the reservation cost be "y" ... Now,
According to question...
One full reserved ticket = 4150 --- (1)
And One full and a half reserved ticket = 6255 ---- (2)
So replacing them with variables...
For (1) You would get "x+y = 4150" --- (eq.1)
For (2) You have, "(x+y)+x/2+y = 6255" --- (eq.2)
[Each ticket will have it's own reservation charge....]
Now in the eq.2
By replacing (x+y) value you get "x/2+y = 2105"
=x+2y = 4210 (*2 both sides) --- (eq.3)
Now solve both (eq.1) and (eq.3)
By solving you get y=60
x=4090
So the Full ticket cost is Rs.4090 and the reservation cost is Rs.60,
half ticket cost is Rs.2045
Good Luck!!
It's a really simple question...
(Directly jump down if you are looking only for answer ; otherwise go through the answer :P)
Look...
Let's take the one full fare as "x" ,
So half fare would be "x/2"
And let the reservation cost be "y" ... Now,
According to question...
One full reserved ticket = 4150 --- (1)
And One full and a half reserved ticket = 6255 ---- (2)
So replacing them with variables...
For (1) You would get "x+y = 4150" --- (eq.1)
For (2) You have, "(x+y)+x/2+y = 6255" --- (eq.2)
[Each ticket will have it's own reservation charge....]
Now in the eq.2
By replacing (x+y) value you get "x/2+y = 2105"
=x+2y = 4210 (*2 both sides) --- (eq.3)
Now solve both (eq.1) and (eq.3)
By solving you get y=60
x=4090
So the Full ticket cost is Rs.4090 and the reservation cost is Rs.60,
half ticket cost is Rs.2045
Good Luck!!
Answered by
16
Answer:
Here is the answer:
Step-by-step explanation:
let the basic first-class full fare be x
and the reservation charge be y
x+y=1450 (full ticket) [1]
one full = x+y
one half = x/2+y
x+y+x/2+y = 6255 [2]
[2] * 2
= 2x+2y+x+2y = 12510
3x+4y = 12510 [3]
x+y = 4150 (equation 1)
(this equation * 3)
= 3x+3y = 12450 [4]
(subtract equation 3 and 4)
=y = 60
substitute:
x+60 = 4150
x = 4090
reservation = Rs 60
basic 1st class full fare = Rs 4090
Hope it help u guys. Please mark it as brainliest
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