Math, asked by deekshitaa, 6 hours ago

A random sample of 10 tins of oil filled in by an automatic machine gave the following weight in kg. 2.05, 2.01, 2.04, 2.98, 1.96, 2.01, 1.97, 199, 2.04, 2.02. Can we accept, at 5% level of significance the claim that the average weight of the tin is 2kg? Given fons (9)= 2.26​

Answers

Answered by PURPLEARMYGIRL173
4

Answer:

random sample of 10 tins of oil filled in by an automatic machine gave the following weights in kg.

random sample of 10 tins of oil filled in by an automatic machine gave the following weights in kg. 2.05, 2.01, 2.04, 1.98, 1.98, 1.96, 2.01, 1.99, 2.04, 2.02

random sample of 10 tins of oil filled in by an automatic machine gave the following weights in kg. 2.05, 2.01, 2.04, 1.98, 1.98, 1.96, 2.01, 1.99, 2.04, 2.02 can we accept at 5% level of significance, the claim that the average weight of the tin is 2kg

random sample of 10 tins of oil filled in by an automatic machine gave the following weights in kg. 2.05, 2.01, 2.04, 1.98, 1.98, 1.96, 2.01, 1.99, 2.04, 2.02 can we accept at 5% level of significance, the claim that the average weight of the tin is 2kgThe mean is 2.008

random sample of 10 tins of oil filled in by an automatic machine gave the following weights in kg. 2.05, 2.01, 2.04, 1.98, 1.98, 1.96, 2.01, 1.99, 2.04, 2.02 can we accept at 5% level of significance, the claim that the average weight of the tin is 2kgThe mean is 2.008the sd is 0.030

random sample of 10 tins of oil filled in by an automatic machine gave the following weights in kg. 2.05, 2.01, 2.04, 1.98, 1.98, 1.96, 2.01, 1.99, 2.04, 2.02 can we accept at 5% level of significance, the claim that the average weight of the tin is 2kgThe mean is 2.008the sd is 0.030t df=9 =0.008/0.030/sqrt(10)

random sample of 10 tins of oil filled in by an automatic machine gave the following weights in kg. 2.05, 2.01, 2.04, 1.98, 1.98, 1.96, 2.01, 1.99, 2.04, 2.02 can we accept at 5% level of significance, the claim that the average weight of the tin is 2kgThe mean is 2.008the sd is 0.030t df=9 =0.008/0.030/sqrt(10)=0.843

random sample of 10 tins of oil filled in by an automatic machine gave the following weights in kg. 2.05, 2.01, 2.04, 1.98, 1.98, 1.96, 2.01, 1.99, 2.04, 2.02 can we accept at 5% level of significance, the claim that the average weight of the tin is 2kgThe mean is 2.008the sd is 0.030t df=9 =0.008/0.030/sqrt(10)=0.843critical value is 2.262

random sample of 10 tins of oil filled in by an automatic machine gave the following weights in kg. 2.05, 2.01, 2.04, 1.98, 1.98, 1.96, 2.01, 1.99, 2.04, 2.02 can we accept at 5% level of significance, the claim that the average weight of the tin is 2kgThe mean is 2.008the sd is 0.030t df=9 =0.008/0.030/sqrt(10)=0.843critical value is 2.262fail to reject Ho at the 5% level.

random sample of 10 tins of oil filled in by an automatic machine gave the following weights in kg. 2.05, 2.01, 2.04, 1.98, 1.98, 1.96, 2.01, 1.99, 2.04, 2.02 can we accept at 5% level of significance, the claim that the average weight of the tin is 2kgThe mean is 2.008the sd is 0.030t df=9 =0.008/0.030/sqrt(10)=0.843critical value is 2.262fail to reject Ho at the 5% level.Answer is yes, the claim of 2 kg average weight is correct.

hope it helps you !!

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