a ray is incident on a mirror at a glancing angle 2g. find the angle of deviation
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Glancing angle is nothing but, the angle between incident ray and the surface of the mirror,
The angle between incident ray and normal ray + the glancing angle = 90°,
let the angle of incidence be I,
and angle of reflection be R ,
The glancing angle = 90-I
the angle of deviation + angle of incidence + angle of reflection = 180°,
We know I = R,
now angle of deviation = 180-2i,
we see that angle of deviation = 2*glancing angle,
according to data, glancing angle = 2g,.
so now the deviation angle = 2*(2g)
So the answer is 4g !
The angle between incident ray and normal ray + the glancing angle = 90°,
let the angle of incidence be I,
and angle of reflection be R ,
The glancing angle = 90-I
the angle of deviation + angle of incidence + angle of reflection = 180°,
We know I = R,
now angle of deviation = 180-2i,
we see that angle of deviation = 2*glancing angle,
according to data, glancing angle = 2g,.
so now the deviation angle = 2*(2g)
So the answer is 4g !
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Answer:
180-4g
Explanation:
The angle between plane mirror and incident or reflected ray is called glancing angle
Glancing angle of incidence is 90-i
Glancing angle of reflection is 90-r
Given glancing angle is 2g
Then we know angle i= angle r
Then 180-2g-2g=α
α=180-4g
Is the angle of deviation
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