A ray light is incident normally on the face AB of a right angled triangle glass prism of refractive index aug = 1.5. The prism is partly immersed in a liquid of unknown refractive index. Find the value of refractive index of the liquid so that the ray grazes along the face BC after refraction through the prism
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refractive index of prism = μg = 1.5
as you can see that, light rays graze along face BC ,when the angle of incident is i is equal to the critical angle for the glass and liquid interface,
e.g., i = 60° [as you can see in figure ]
now, μl × sin90° = μg × sini
μl = 1.5 × sin60° = 1.5 ×√3/2 = 1.2975
hence, refractive index of liquid is 1.2975 ≈ 1.3
as you can see that, light rays graze along face BC ,when the angle of incident is i is equal to the critical angle for the glass and liquid interface,
e.g., i = 60° [as you can see in figure ]
now, μl × sin90° = μg × sini
μl = 1.5 × sin60° = 1.5 ×√3/2 = 1.2975
hence, refractive index of liquid is 1.2975 ≈ 1.3
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1.3
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