Question

A ray of light enters into diamond from air. If the refractive index of diamond is 2.42 what percent is the speed of light in diamond to that of air

Answer 1

Refractive index μ = c/v . where c and v are speed of light in air and refracting medium respectively.

 

hence v = c/μ = c/2.42 = 0.413×c

 

hence speed of light in diamond is reduced to 41.3% of original value in air

Answer 2

Given that,

The refractive index of diamond is 2.42

To find,

What percent is the speed of light in diamond to that of air?

Solution,

The ratio of speed of light in vacuum to the speed of light in medium is call refractive index of the medium such that,

$n=\dfrac{c}{v}\\\\v=\dfrac{c}{n}$

c is speed of light in vacuum

$v=\dfrac{c}{2.42}\\\\v=0.413\ c$

It means that the speed of light is reduced to 41.3% of original value in air.

Learn more,

Refractive index

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