A reaction is second order with respect to a reactant. How is the rate affected if the concentration is reduced to half? What is the unit of rate constant
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Hey !!
Consider the reaction nR -------> Products
As the reaction is of second order
Rate, r = k [R]² -------> (1)
If the concentration of the reactants reduced to half, then
Rate, r' = k[R/2]² -----------> (2)
Dividing equation (2) by (1), we get
r'/r = k[R]² / 4k [R]² = 1/4
r' = 1/4r , rate of reaction becomes 1/4th of the initial state.
Therefore, the unit of rate constant is mol⁻¹L s⁻¹
Hope it helps you !!
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