Question

A reaction required three atoms of Mg for two atoms of N. How many gm of N are required for 3.6 gm of Mg

Answer 1

Answer:

CHEMISTRY

A reaction required three atoms of Mg for two atoms of N. How many grams of N are required for a 3.6 g of Mg?

December 20, 2019avatar

Huda Behl

SHARE

VIDEO EXPLANATION

ANSWER

As given, three moles of Mg require two moles of N.

So, 3×24 (molecular mass of Mg) mass of Mg will require 2×14 (molecular mass of N) mass of N.

So, N required for 3.6 g of Mg =

72

28

×3.6=1.4 g.

Explanation:

plz mark me as brainlist