Question

A reaction required three atoms of Mg for two atoms of N. How many gm of N are required for 3.6 gm of Mg

Answer 1

Answer:

3 atoms of Mg = 2 atoms of N

hence,

3.6 gram of Mg = x gram of N

therefore,

gram of N required=(2×3.6)/3

=7.2/3

=2.4gm

2.4 gram of nitrogen is required