Question

A reaction required three atoms of Mg for two atoms of N. How many gm of N are required for 3.6 gm of Mg

Answer 1

Answer:

As given, three moles of Mg require two moles of N.

So, 3×24(molecular mass of Mg)

mass of Mg will require 2×14 (molecular mass of N) mass of N..

So, N required for 3.6 g of Mg =

=(28/72) ×3.6

=1.4g