Question

a rear view mirror has focal length 6m a 3m high car is seen and a image is formed 3m behind the mirror find object distance and size

Answer 1

object distance (u)= -5m (always negative)

radius of curvature C = 3m

focal length = 3/2 = 1.5m.

with formula we know that ,

1/v +1/u = 1/f

1/v = 1/1.5 - 1/-5

1/v = -5 - 1.5 /-7.5

1/v = -6.5/-7.5

v = 1.15m

we must find magnification,

m= -v/u

= -1.15/-5

=0.23 

the image is formed on the opposite side of the object.so it will be virtual and erect.

and 0.23 is very small where the object is placed beyond C.

so the image is virtual ,diminished and erect.

hope it helps!!!!