Math, asked by ponung9687, 1 year ago

A RECENT SURVEY FOUND THAT THE AGES OF WORKERS IN FACTORY ARE DISTRJBUTED AS

AGE IN YRS 20-29,30-39.40-49,50-59,60 AND ABOVE

NO.OF WORKERS 38,27,86,46,3

IF A PERSON IS SELECTED AT RANDOM FIND THE PROBABILITY THAT THE PERSON IS

1. 40 YRS OR MORE

2.UNDER 40YRS

3.UNDER 60 BUT NOT OVER 39YRS

Answers

Answered by rajasekarvenkatesan
150

Answer:


Step-by-step explanation:

1. P( worker aged 40 or more) = 135/200 = 27/40

2. P(worker aged under 40) = 65/200 = 13/40

3. P(worker aged below 60 but not over 39) = 13/40


Hope for brainliest!!!

Answered by madeducators1
6

Given:

We have given

Age in years: 20-29,30-39.40-49,50-59,60 AND ABOVE

NO.OF WORKERS 38,27,86,46,3

To Find:

Probability of different possibilities?

Step-by-step explanation:

  • First of all, we find the total number of workers by adding all the workers given to us which is given by
  • Total no. of workers=38+27+86+46+3=200

          Now we have that a person is selected at random from given workers

  • 1) Find the probability the person is 40 years or more in age?

       Total number of worker=200

       Number of people more then age 40 =86+46+3=135

  • Hence probability is given by the formula

         P(E)=\frac{\textrm{no. of favorable outcome}}{\textrm{total no. of outcome}} \\\\P(40 years, or more)=\frac{135}{200} =\frac{27}{40}

  • 2) Find the probability the person is under 40?

       Total number of worker=200

       Number of person under age 40 =38+27=65

  • Hence probability is given by the formula

         P(E)=\frac{\textrm{no. of favorable outcome}}{\textrm{total no. of outcome}} \\\\P(  less,40 years)=\frac{65}{200} =\frac{13}{40}

  • 3) Find the probability the person is under 60 but not over 39 years?

      Total number of worker=200

      Number of a person under age 40 over 39 years =86+46=132

  • Hence probability is given by the formula

        P(E)=\frac{\textrm{no. of favorable outcome}}{\textrm{total no. of outcome}} \\\\P(  less,60 years)=\frac{132}{200} =\frac{66}{100}

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