Question

A rectangle has an area of 161.2m2.
One of the sides is 5.2m in length.
Work out the perimeter of the rectangle I don't know what you have to doths

Answer 1

Given :-

Area of rectangle =161.2m^2

One of its side is 5.2m

To find :-

The perimeter of rectangle

A.T Q :-

let the second side be x

Now we know that

•Area of rectangle=length ×breadth

So Find the other side of rectangle

=> l×b= Area

=> 5.2 × x=161.2

=> x=161.2/5.2

=> x= 31m

• So the other side of rectangle is 31m

Now find the Perimeter

Perimeter of rectangle=2(l+b)

=> Perimeter= 2(5.2+31)

=> perimeter= 2× 36.2

=> Perimeter= 72.4m

Perimeter of rectangle is 72.4m

Answer 2

Given :

• Area of the rectangle → 161.2 m²
• One of the side is 5.2 m in length.

To Find :

• Perimeter of the rectangle.

Solution :

Let the length of the rectangle be x m.

Let the breadth of the rectangle be y which is equal as 5.2 m

Area → (x) (y)

Formula :

$\large{\boxed{\sf{\purple{Area_{Rectangle}\:=\:Length\:\times\:Breadth}}}}$

Block in the data,

$\longrightarrow$ $\sf{161.2=x\:\times\:y}$

$\longrightarrow$ $\sf{161.2=x\:\times\:5.2}$

$\longrightarrow$ $\sf{\dfrac{161.2}{5.2}\:=\:x}$

$\longrightarrow$ $\sf{31=x}$

$\large{\boxed{\sf{\red{Length\:of\:the\:rectangle\:=\:x\:=\:31\:m}}}}$

Now, for calculating the perimeter of the rectangle, we have all the required quantities.

So just use the formula, block in the data and find the perimeter.

Formula :

$\large{\boxed{\blue{\tt{Perimeter_{Rectangle}\:=\:2(l+b)}}}}$

Block in the values,

$\longrightarrow$ $\sf{2(31+5.2)}$

$\longrightarrow$ $\sf{62+10.4}$

$\longrightarrow$ $\sf{72.4}$

$\large{\boxed{\sf{\green{Perimeter\:of\:rectangle\:=\:72.4m}}}}$