A rectangle has the perimeter of 216cn and the area of 800cm², find the diagoal of rectangle.
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Perimeter of rectangle =216
2(l+b) =216
l+b=216/2
l+b=108cm
And
Area of rectangle =lenght *breadth =l*b
800=l*b
Diagonal² =l²+b²
(l+b) ²=l²+b²+2(lb)
(108)²=l²+b²+2(800)
11664=l²+b²+1600
10064=l²+b²
As l²+b²=diagonal²
10064=diagonal²
100.31949 is the lenght of diagonal
2(l+b) =216
l+b=216/2
l+b=108cm
And
Area of rectangle =lenght *breadth =l*b
800=l*b
Diagonal² =l²+b²
(l+b) ²=l²+b²+2(lb)
(108)²=l²+b²+2(800)
11664=l²+b²+1600
10064=l²+b²
As l²+b²=diagonal²
10064=diagonal²
100.31949 is the lenght of diagonal
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