Question

A rectangle is 16m by 9m .Find a side of the square whose area equals the area of the rectangle.By how much does the perimeter of the rectangle exceed the perimeter of the square?

Answer 1

It is given that A rectangle is 16m by 9m. Hence,the area of the rectangle is length*breadth
= 16*9 = 144 square metres.
It is given that the area of a square equals the area of the rectangle.
Thus the area of the square = 144. Hence it's side is root of 144 which is 12 metres.
To find how much the perimeter of the rectangle exceeds the perimeter of the square, we need to find out each perimeter first.
Rectangle perimeter = 2( l + b)
= 2( 16+9)
= 50 metres.
Square perimeter = 4*side
= 4*12
= 48 metres.
Thus it's perimeter exceeds by 50 - 48 = 2 metres.
It exceeds by 2 metres.
Hope this helps!

Answer 2

Answer:

Heya mate

Here's your answer