A rectangle is of length 8 inches, breath 11 inches and thickness 2 inches. when it is shaped to a cylindrical rod with the diameter is 10m. what is the height of the cylinder?
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Answer:
For Rectangle:-
We have given length of rectangle= 8 inches
Breadth of rectangle= 11 inches
Thickness of rectangle= 2 inches
For Cylinder:-
We have given diameter= 10m
Therefore, Radius= d/2
= 10m/2
= 5m
Now, we have given dimensions of rectangle in inches and cylinder in meters.
With the given dimensions of rectangle, Volume(in m³)=8×11×2×(0.0254)³
=0.00288 m³ =cylinder's volume
Let cylinder's height=h
Radius is=5 m
Then by formula πr²h,
(22/7)×(25)×h= 0.00288
(550/7)×h=0.00288
h=0.00288×7/550
h=0.0216/550 m
Therefore, height of cylinder= 0.0216/550 m or 3.66545455e-5
Step-by-step explanation:
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