Question

A rectangular beam of 10 cm width, is subjected to a maximum shear force of 50 kn and the corresponding maximum shear stress is 3 mpa. The depth of the beam is

Answer 1

Answer:

We know, maximum shear stress = 3 × shearing force/2 {area of rectangular beam}

Given,

maximum shear stress = 3MPa = 3 × 10^6 Pa

shearing force = 50kN = 50 × 10³ N

breadth of rectangular beam = 10cm = 0.1 m

Let depth of beam is D

then, 3 × 10^6 = 3 × 50 × 10³/2 × 0.1 × D

3 × 10³ = 150/0.2D

3 × 10³ = 750/D

D = 750/3 × 10³

D = 250 × 10^-3 m = 250 mm

hence, depth of beam = 250mm

Explanation:

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