A rectangular box 80into50into30cm is to be painted from outside at the rate of 12.5per sq.m.find the cost of painting the box
Answers
Answer:
Given,
Length = 80cm
Breadth=50cm
Height=30cm
TSA of cuboid = 2(lh+bh+lh)
2(80 x 50+50 x 30+80 x 30)
2(4000+1500+2400)
2(7900)
15800 sq m
Cost of painting box for 1m =12.5
Cost of painting box for 15800=15800 x 12.5=197500
Given - Dimensions of rectangular box or cuboid = 80*50*30 cm
Cost of painting = Rs. 12.5/m²
Find - Cost of painting the box
Solution - The total surface area of rectangular box is given by the formula = 2(lb + bh + lh). In the formula, l represents length, b represents breadth and h represents height.
Keeping the values in formula to find the value of Total Surface Area of rectangular box.
Total surface area = 2(80*50 + 50*30 + 80*30)
Total surface area = 2(4000 + 1500 + 2400)
Total surface area = 2(7900)
Total surface area = 15800 cm²
Total surface area = 1.58 m²
Calculating the cost of painting this rectangular box.
Painting of 1 m² costs Rs. 12.5
Painting of 1.58 m² will cost = 12.5*1.58
Painting of rectangular box will cost = Rupees 19.75
Thus, cost of painting the box is Rupees 19.75