Question

a rectangular courtyard 18 metre 72 cm long and 13 M 20 CM broad is to be paved with square stones of the same size. find the least possible number of such stones.

Answer 1

Hello! !!!

here is your answer,

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length of courtyard = 18m  72cm = 1872cm

breadth of courtyard = 13m 20cm = 1320 cm

take HCF of 1872 and 1320

1872 = 1320 * 1 + 552

1320 = 552 * 2 + 216

552 = 216 * 2 + 120

216 = 120 * 1 + 96

120 = 96 *1 +24

96 = 24 * 4 + 0

HCF of 1872 and 1320 = 24

no of tiles = area of courtyard / area of side of tile

                   = 1872 * 1320 /24 *24

                   = 4290 

4290 tiles of same size can paved  in the rectangular courtyard.

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Hope it helps u :))

# Nikky

Answer 2

here is your answer.....

length of courtyard = 18m 72cm

= 1872cm

breadth of courtyard = 13m 20cm = 1320cm

length of a side of square tile
= HCF of 1872 and 1320

= 24

therefore ,no. of tiles required
$= \frac{area \: of \: rectangular \: courtyard}{area \: of \: 1 \: tile} \\ = \frac{1872cm \: \times 1320cm}{24cm \times 24cm} \\ = 4290$
hence, 1490 tiles are required for paving the rectangular courtyard

hope this helps

with regard,
☆Misa