The volume of cuboid is polynomial p(x) =8x^3+12x^2-2x-3 find possible expressions for dimensions of the cuboid verify the result by taking x=5 units Hey i want this answer
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Answered by
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heya man !! here is the answer !!!
volume can be factorised as :-
=> 8x³+12x²-2x-3
=> 2x(4x²-1) +3(4x²-1)
=> (2x+3)(2x+1)(2x-1)
hence, the possible dimensions are :-
(2x+3), (2x+1),(2x-1)
if x= 5
hence the dimensions are 13 ,11 and 19 .
therefore ,
13×11×19 = 1287 unit³
hope that helps !!
@ himanshu Jha
be happy and live longer my friend !!!✌✌
volume can be factorised as :-
=> 8x³+12x²-2x-3
=> 2x(4x²-1) +3(4x²-1)
=> (2x+3)(2x+1)(2x-1)
hence, the possible dimensions are :-
(2x+3), (2x+1),(2x-1)
if x= 5
hence the dimensions are 13 ,11 and 19 .
therefore ,
13×11×19 = 1287 unit³
hope that helps !!
@ himanshu Jha
be happy and live longer my friend !!!✌✌
Anonymous:
vanshika
may i know
What
in which class u r ??
This question is given me in holidays homework
Dont chat here...
i mean the question u have asked is frm which class
okk
sidhatrtharao
9 class
Answered by
0
Given f(x) = 8x^3 + 12x^2 - 2x - 3.
= > 2x(4x^2 - 1) + 3(4x^2 - 1)
= > (2x + 3)(4x^2 - 1)
= > (2x + 3)((2x)^2 - (1)^2)
We know that a^2 - b^2 = (a + b)(a - b)
= > (2x + 3)(2x + 1)(2x - 1)
Substitute x = 5, we get
= > (2(5) + 3)(2(5) + 1)(2(5) - 1)
= > (13)(11)(9)
= > 1287.
Now,
Substitute x = 5 in f(x), we get
= > 8(5)^3 + 12(5)^2 - 2(5) - 3
= > 1000 + 300 - 10 - 3
= > 1287.
Therefore 8x^3 + 12x^2 - 2x - 3 = (2x + 3)(2x - 1)(2x + 1).
Hence verified!
Hope this helps!
= > 2x(4x^2 - 1) + 3(4x^2 - 1)
= > (2x + 3)(4x^2 - 1)
= > (2x + 3)((2x)^2 - (1)^2)
We know that a^2 - b^2 = (a + b)(a - b)
= > (2x + 3)(2x + 1)(2x - 1)
Substitute x = 5, we get
= > (2(5) + 3)(2(5) + 1)(2(5) - 1)
= > (13)(11)(9)
= > 1287.
Now,
Substitute x = 5 in f(x), we get
= > 8(5)^3 + 12(5)^2 - 2(5) - 3
= > 1000 + 300 - 10 - 3
= > 1287.
Therefore 8x^3 + 12x^2 - 2x - 3 = (2x + 3)(2x - 1)(2x + 1).
Hence verified!
Hope this helps!
:-)
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