Question

a rectangular field 80 m length and 48 m breadth. three roads each of width 2 m pass through the feild such that two roads are parallel to the breadth and the third road parllal to the length. find the area coverd by the three roads.

Answer 1

length=80m
breadth=48m
as given there are 3 roads 
2 are parallel to the breadth and their width is 2m so their
therefore width = length 1 road of those 2 roads 
breadth of the road= 48m
so area
l*b
2*48
96
there are 2 roads
therefore, 96*2=192m
now the 3rd road which is parallel to the length and width 2m
therefore, length=width...length=2m
breadth=length....breadth=80m
area,
l*b
2*80
160m
now total covereved by all 3 roads
160m+192(of those 2 roads)
=352m
(i just tried to solve it i dont know if its 100%correct)

Answer 2

Answer:

Area covered by the three roads is 344 m²

Step-by-step explanation:

Area of a rectangle = length * breadth

For the area of the 2 roads ||el to the breadth

Area = 2 [ 48 * 2 ]

Area = 192 sq. m

For the area of the road ||el to the length

Area = [ 80 * 2 ]

Area = 160 sq. m

So, the total area of the 3 roads = 192 + 160 = 352 sq. m

But these roads will intersect forming 2 squares of 2m x 2m dimensions of area 4 sq. m each

So, the total area actually covered by the roads

= 352 - (2*4) = 344 sq. m

Hope you have got it