a rectangular field which length and breadth are 200m and 120m respectively.a well is dug out in its middle 28m its diameter and 8m depth.find how much level rise of the field.
Answers
Answer:
If a 24m x 12m x 8m tank is dug out of 600m * 200m rectangular field, then the level of the field will rise up to 1.92 cm.
Step-by-step explanation:
Step 1:
Length of the rectangular field = 600 m
Breadth of the rectangular filed = 200 m
∴ The area of the rectangular field = Length x Breadth = 600 * 200 = 120000 m²
Step 2:
For the rectangular tank:
Length = 24 m
Breadth = 12 m
Height = 8 m
∴ The area of the base of the tank = l * b = 24 * 12 = 288 m²
∴ The area of the rectangular field excluding the tank is given by,
= [The area of the rectangular field] – [The area of the base of the tank]
= 120000 – 288
= 119712 m²
Step 3:
Now, it is given that the amount of earth taken was used to level the rectangular field, so
[Volume of the rectangular tank] = [Area of the rectangular field excluding the tank] * [Rise in level of field]
Therefore, we can write
24*12*8 = 119712 * [Rise in level of field]
⇒ 2304 = 119712 * [Rise in level of field]
⇒ [Rise in level of field] = 0.0192 m = 1.92 cm
Thus, the filed will rise up to a level of 1.92 cm.