Question

A rectangular frame of wire n25cm × 15 cm is placed in a uniform electric field of strength 3×10³ N/c, such that the plane of the coil is normal to the field. Find the electric flux linked with the rectangular frame.​

Answer 1

Given:

A rectangular frame of wire 25cm × 15 cm is placed in a uniform electric field of strength 3×10³ N/c, such that the plane of the coil is normal to the field.

To find:

Net electric flux associated with the rectangular frame.

Calculation:

Let flux be denoted as $\phi$.

$\therefore \: \phi = E \times A \times \cos( \theta)$

$= > \: \phi = E \times A \times \cos( 0 \degree)$

$= > \: \phi = E \times A$

Putting available values in SI unit:

$= > \: \phi = 3 \times {10}^{3} \times \bigg( \dfrac{25 \times 15}{10000} \bigg )$

$= > \: \phi = 3 \times \cancel{ {10}^{3}} \times \bigg( \dfrac{25 \times 15}{10 \cancel{000}} \bigg )$

$= > \phi = 112.5 \: \: N {m}^{2} {C}^{ - 1}$

So, final answer is:

$\boxed{ \red{ \bold{ \phi = 112.5 \: \: N {m}^{2} {C}^{ - 1} }}}$