Question

A rectangular garden is 60 m long and 40m wide. Through the middle of the garden run two strait paths at right angles to each other. If the width of each path is 2m,find the area of the remaining portion of the garden.

Answer 1

Area of the rectangle = Length×Breadth=65×50=3250m2Length×Breadth=65×50=3250m2

Given Width of the Path = 2m

Length of the Path is Parellel to the side , Hence Length = 65 m

Area of the Path 1 = Length×Width=65×2=130m2Length×Width=65×2=130m2

Given Breadth of the Path = 2m

Length of the Path2 is Parellel to the other side , Hence Length = 50 m

Area of the Path2 = Length×Breadth=50×2=100m2Length×Breadth=50×2=100m2

Add Both the Area of the Path = 130+100=230m2130+100=230m2

Area of the Common Field ABCD = 2×2=4m22×2=4m2

As both path are overlapping each other, so to calculate the area of shaded portion area of one square should be deducted from the area of the total path.

∴∴ Total Area for the Path Construction = 230−4=226m2230−4=226m2

∴∴ Cost of Constructing the Path = 230−4=226×69=15594

HEY MATE PLEASE MARK ME AS A BRAINLIST ANSWER

Answer 2

hey mate as u can see in the above pic

the length of each garden part is 19m

and breath is 29 m

and there are 4 parts

so the area of remaining portion of the garden

=4 × (l + b )

=4 × ( 19 × 29 )

=4 × 551

=2204 cm square

the answer given by another mate is wrong

u can compare with the question

so plzzzzzz mark as brainliest