Math, asked by ganeshmganesh225, 1 year ago

a rectangular ground is 90m long and 32m broad in its centere there is a circular tank of radius 14m find the cost of remaining portion at the rate of 2.50 per m^2

Answers

Answered by amankumaraman11
5
Hey There!


area \: of \: whole \: ground = (90 \times 32) {m}^{2}
 = 2880 {m}^{2}


area \: of \: circle =  \pi \times  {r}^{2}  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \frac{22}{7}  \times 196

 = 616 {m}^{2}

Now,

area \: of \: field \: excluding \: circle =  (2880 - 616) {m}^{2}

required \: area = 2264 {m}^{2}

Hence,

total \: required \: cost = (2.50 \times 2264)

₹ 5660 will be required for furnishing of remaining portion of the field excluding circle.









PLEASE MARK ME BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST
Similar questions