Question

A rectangular hall 20 m long and 4.5m broad is to be covered with square tiles. if the side of each square tile is 3m, then find the number of tiles required to cover the floor

Answer 1

Answer:

may it help you,

Step-by-step explanation:

for rectangular hall,

length=20m

breadth=4.5m

area of rectangular hall=l ×b

                                      = 20 ×4.5

                                       =90 m

for square tiles,

side = 3m

area of square tile= side²

                              =3²

                              =9 m

let the no.of tiles required be x

no.of tilesrequired× area of each tile= area of rectangular hall

x                              =area of rectangular hall/area of each tile

x                             =90 m/9 m

x  =10

∴no.of tiles required to cover the floor are 10.

Answer 2

$\tt ฏGIVEN:−$

$\tt length \: of \: floor = 4m =400cm$

$\tt breadth\: of \: floor= 3m = 300cm$

$\tt length\: of \: single \: tile= 8cm$

$\tt breadth\: of \: single \: tile= 6cm$

$\tt ฏFIND:-$

$\tt no. \: of \: tiles \: reqire = ?$

$\tt ฏSOLUTION:-$

$\tt area \: of \: floor = 400 \times 30 \\ \tt = 120000 {cm}^{2}$

$\tt area \: of \: each \: tile= 8 \times 6 = 4 {cm}^{2}$

$\tt now \: let \: no. \: of \: tiles = x$

$\tt = > area \: of \:hall= x\times area \: of \: each$

$\tt = > 120000 = x(48)$

$\tt = > x = \frac{ \cancel{ 120000}}{ \cancel{48}} = 2500$

$\boxed{ \tt so \: total \: no. \: of \: tile \: is \boxed{2500}}$