A rectangular piece of paper 22 cm long and 12 cm broad is rolled along its length to form a cylinder. Find the total surface area of the cylinder so formed, supposed the top and bottom is clossed
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Answered by
3
heya mate here... is ur answer.
when u roll up the rectangular paper..
it's length is converted into cylinder 's circumference..
So, 2πr=22cm. so, r= 3.5 cm
and height = breadth of paper = 12.
so t. s. a of cylinder = 2πr(h+r)
=341
hope u r helped
when u roll up the rectangular paper..
it's length is converted into cylinder 's circumference..
So, 2πr=22cm. so, r= 3.5 cm
and height = breadth of paper = 12.
so t. s. a of cylinder = 2πr(h+r)
=341
hope u r helped
Answered by
0
Answer:
341 is right answer
341
341
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