Question

A rectangular sheet of paper is 23/2 cm long and 32/3 cm wide. find its perimeter and area​

Answer 1

Given :-

$\sf\bullet { Length\:=\: \frac{23}{2}\:cm}$

$\sf\bullet{Breadth\:=\: \frac{32}{3}\:cm}$

To find :-

$\sf\bullet { Area}$

$\sf\bullet{Perimeter}$

Formula used !

$\sf\boxed{Area\:=\:Length \times Breadth}$

$\sf\boxed{Perimeter\:=\: 2 (L+B) }$

Solution

$\huge\bf{1.}$

$\sf{Perimeter\:=\:2(L+B)}$

$\sf{Perimeter\:=\:2(\frac{23}{2}+\frac{32}{3})}$

$\sf{Perimeter\:=\:2(\frac{69+64 }{6})}$

$\sf{Perimeter\:=\: \cancel{2}\times \frac{133}{\cancel{6}}}$

$\sf{Perimeter\:=\:\frac{133}{3}}$

$\sf{Perimeter\:=\:44.34\: cm}$

$\huge\bf{2.}$

$\sf{Area\:=\:Length \times Breadth}$

$\sf{Area\:=\:\frac{23}{2} \times \frac{32}{3}}$

$\sf{Area\:=\:\frac{736}{6}}$

$\sf{Area\:=\:122.6 \: \ cm^{2}}$

Answer 2

Perimeter=2×(L+B)

Perimeter of the sheet of paper=2×(23/2+32/3)

=2×22.16

Answer=44.33cm

Area=L × B

=(23/2×32/3)cm²

=122.66cm²

Hope it helps you