Question

find the zeroes of the polynomial
p(t) =t^2+3t+2
Friends I don't want answer only I wanted the explaination​

Answer 1

Answer: t = -1 , -2

Step-by-step explanation:

To find zeroes equate polynomial to 0.

p(t) = t² +3t +2 =0

t² + t +2t +2=0

t(t+1) +2 (t+1) =0

(t+2)(t+1)=0

t = -2,-1

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Answer 2

$p(t) = {t}^{2} + 3t + 2$

THIS QUESTION WILL BE SOLVED BY HIT AND TRIAL METHOD.

THAT IS PUT NUMBER IN PLACE OF t.

$let \: t = 1 \\ {1}^{2} + 3(1) + 2 \\ 2 + 3 + 2 \\ 7$

This is not equal to zero

Hence, 1 is not the zeroes of the polynomial p(t).

$let \: t = - 1 \\ { - 1}^{2} + 3( - 1) + 2 \\ 1 - 3 + 2 \\ 0$

Hence, - 1 is the zeroes of the polynomial p(t).

Smilarly you can solve any question just by this method.

You can also find one or more zeroes of the given polynomial.

Find by putting values in place of t.

( 2,-2,3,-3........)

HOPE THIS HELPS YOU

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