Question

A rectangular sheet of paper is
5.23 cm long and 3.15 CM wide find perimeter​

Answer 1

$Perimeter = 2(l + b)$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2(5.23 + 3.15)$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \times 8.38$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 16.76\:cm$

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Answer 2

Answer:

16.76cm

Step-by-step explanation:

• The formula to find the perimeter of a rectangle is given below:

2(l+w)  Where 'h' is the height and 'w' is the width.

If the rectangle is 5.23cm long, it means that the height of the rectangle is 5.23cm, and if the rectangle is 3.15cm wide, it means that the width of the rectangle is 3.15cm.

• Substituting the values, we get:

2(5.23+3.15)

2(8.38)

=> 16.76

Therefore, the area of the rectangular sheet of paper is 16.76cm.

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