A rectangular solid block has sides 4cm by 10cm by 20cm and its weight is 40N. if it rests on a horizontal flat surface, calculate the minimum and maximum pressure it exerts
Answers
Given data : A rectangular solid block has sides 4cm by 10cm by 20cm and its weight is 40N. It rests on a horizontal flat surface,
To find : calculate the minimum and maximum pressure it exerts.
Solution : As per given data we know that shape of solid block is cuboid. Here we know, opposite site faces of cuboid are equal.
Let, diamension's of solid block as follows :
- Length of block = 4 cm
- Width of block = 10 cm
- Height of block = 40 cm
Force act by solid block to horizantal flat surface is 40 N. We can place the solid block in 3 ways so,
Now, we use formula of pressure,
⟹ Pressure = Force/Area
⟹ Pressure = 40/(length * width)
⟹ Pressure = 40/(4 * 10)
⟹ Pressure = 40/40
⟹ Pressure = 1 pa ----{1}
⟹ Pressure = Force/Area
⟹ Pressure = 40/(length * height)
⟹ Pressure = 40/(4 *40)
⟹ Pressure = 40/160
⟹ Pressure = 0.25 pa ----{2}
⟹ Pressure = Force/Area
⟹ Pressure = 40/(width * height)
⟹ Pressure = 40/(10 * 40)
⟹ Pressure = 40/400
⟹ Pressure = 0.1 pa ----{3}
Answer : Hence, from {1}, {2} and {3} maximum pressure is 1 pa and minimum pressure is 0.1 pa.
[ 1 pa > 0.25 pa > 0.1 pa]