A rectangular tank has length=5 m and breadth=3m .It is filled with water upto 60 cm depth.Find :
(i) volume of water in the tank .
(ii) area of walls ,I In the tank ,iinnn contact of water.
(iii) the wetted surface area of the tank . solve
Answers
Answered by
6
1-volume=5×3×.6
=9 m³
2-area of four wall +area of rectangle =2(l+b)h+lb
=2(5+3)×·6+5×3
=16×·6+15
=9·6+15
=24·6 m²
3-total surface area=2(lb+bh+hl)
=2(15+1·6+3)
=2×19·6
=39·2 m²
=9 m³
2-area of four wall +area of rectangle =2(l+b)h+lb
=2(5+3)×·6+5×3
=16×·6+15
=9·6+15
=24·6 m²
3-total surface area=2(lb+bh+hl)
=2(15+1·6+3)
=2×19·6
=39·2 m²
kiara4:
actually the last answer is wrong and u have not mentioned the second answer
Answered by
2
1
1
1
1)v=l*b*h
=5*3*60
=15*60
3000
v=3000
2)area of walls
5*60(assuming ht to be same has water filled )
3*60
300+180
480
3)5+5+3+3=16*60=960
960 wetted surface in ythe tank
1
1
1)v=l*b*h
=5*3*60
=15*60
3000
v=3000
2)area of walls
5*60(assuming ht to be same has water filled )
3*60
300+180
480
3)5+5+3+3=16*60=960
960 wetted surface in ythe tank
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