show that 2^55 +1 is divisible by 11
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( 25 )11 + 1
= 3211 + 1
Now We assume n = 11 , SO
= 32n + 1
And we substitute n = 1 , And get
= 32 +1 = 33 ( That is divisible by 11 )
Now we substitute n = 2 , And get
= 322 +1 = 1024 + 1 = 1025 ( That is not divisible by 11 )
And
Now we substitute n = 3 , And get
= 323 +1 = 32768 + 1 = 32769 ( That is divisible by 11 )
And
Now we substitute n = 3 , And get
= 324 +1 = 1048576 + 1 = 1048577 ( That is divisible by 11 )
SO, we can say at n = odd numbers ( 1 , 3 , 5 , .... ) we get 32n + 1 is divisible by 11 .
And for our query we have n = 11 , that is a odd number , SO we can say that
3211 + 1 is divisible by 11 ,
= 3211 + 1
Now We assume n = 11 , SO
= 32n + 1
And we substitute n = 1 , And get
= 32 +1 = 33 ( That is divisible by 11 )
Now we substitute n = 2 , And get
= 322 +1 = 1024 + 1 = 1025 ( That is not divisible by 11 )
And
Now we substitute n = 3 , And get
= 323 +1 = 32768 + 1 = 32769 ( That is divisible by 11 )
And
Now we substitute n = 3 , And get
= 324 +1 = 1048576 + 1 = 1048577 ( That is divisible by 11 )
SO, we can say at n = odd numbers ( 1 , 3 , 5 , .... ) we get 32n + 1 is divisible by 11 .
And for our query we have n = 11 , that is a odd number , SO we can say that
3211 + 1 is divisible by 11 ,
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