a rectangular Yard contains two flower beds in a shape of congruent isosceles right triangle the remaining portion is the head of trapezoidal Shape whose parallel sides have length 15 M and 25 m what fraction of the yard is occupied by the flower bed
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Answered by
32
hiii!!!by
here's ur answer...
given the Length of the yard is 25m and breadth is 15m
area of the yard = l×b
= 25×15
= 375m²
given that the flower bed is in the shape of isosceles triangle.
we know that the two sides of an isosceles triangle is same.
therefore in the given figure, height and base is same.
area of the flower bed = 1/2×b×h
= 1/2×15×15
= 7.5×15
= 112.5m²
there are two equal flower beds so total area occupied by flower bed is = 112.5×2
= 225m²
hence, fraction of the yard occupied by the flower bed = 225/375
= 45/75
= 9/15
= 3/5
hope this helps..!
here's ur answer...
given the Length of the yard is 25m and breadth is 15m
area of the yard = l×b
= 25×15
= 375m²
given that the flower bed is in the shape of isosceles triangle.
we know that the two sides of an isosceles triangle is same.
therefore in the given figure, height and base is same.
area of the flower bed = 1/2×b×h
= 1/2×15×15
= 7.5×15
= 112.5m²
there are two equal flower beds so total area occupied by flower bed is = 112.5×2
= 225m²
hence, fraction of the yard occupied by the flower bed = 225/375
= 45/75
= 9/15
= 3/5
hope this helps..!
Answered by
36
Answer:
Step-by-step explanation:
Length (AB) of rectangular yard = 25m
FE = 15m ( given )
AB = CD = 25m ( opp. sides of rectangle )
CD = DF + FE + EC
25 = DF + 15m + EC
as DF = EC ( given )
DF = EC = 5m
& also DF = AD & EC = CB ( given )
therefore AD = BC = 5m ( given )
Area of rectangular yard = l × b
= 25 × 5
= 125m2
Area of 2 isosceles congruent flower beds = 2×1/2×b×h
= 5×5
= 25m2
Therefore fraction of yard occupied by flower bed = Area of flower bed / Area of rectangular yard
= 25/125
= 1/5
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