Question

A red-brown metal X forms a salt XSO4. When hydrogen sulphide gas is passed through an aqueous solution of XSO4, then a black precipitate of XS is formed alongwith sulphuric acid solution.
(a) What could the salt XSO4 be?
(b) What is the colour of salt XSO4?
(c) Name the black precipitate XS.
(d) By using the formula of the salt obtained in (a) above, write an equation of the reaction which takes place when hydrogen sulphide gas is passed through its aqueous solution.
(e) What type of chemical reaction takes place in this case?

Answer 1

(a) The salt $XSO_4$ is copper sulphate $(CuSO_4)$.

(b) The colour of the salt $CuSO_4 (XSO_4)$ is blue.

(c) The black precipitate is copper sulphide $CuS (XS)$.

(d) Chemical reaction is:

$\mathrm{CuSO}_{4}+\mathrm{H}_{2} \mathrm{S} \rightarrow \mathrm{CuS}+\mathrm{H}_{2} \mathrm{SO}_{4}$

(e) The type of reaction taking place is double displacement reaction.

Explanation:

• Copper sulphate is a blue coloured compound. It is used in fungicides and used in dyes for its colour.
• Copper sulphide is mineral and synthetic compound which is an important ores. This extraction process involves froth flotation process. It is then smelted and transported for usage.  
• The double displacement reaction is a reaction takes place between two reactants. The element in the reactants interchanged to produce the two products.

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