There are three substances X, Y and Z. The substance X does not have a fixed melting point or boiling point and it still shows the individual properties of its constituents. The substance Y is a pure substance which occurs in nature as such. The substance Y has a fixed melting point and boiling point but it cannot be broken down into simpler substances by any chemical means. The substance Z is also a pure substance whose properties are entirely different from those of its constituents. The substance Z can however, be divided by electrolysis into two substances which belong to the same class of substances as Y.
(a) What type of substance could X be ? Name one substance like X.
(b) What type of substance could Y be ? Name one substance like Y.
(c) What type of substance could Z be ? Name one substance like Z.
(d) Which process involves absorption or release of an appreciable amount of energy formation of substance X or formation of substance Z ?
(e) Name the three groups into which all the substances like Y are divided on the basis of their properties.
Answers
a. Substance X does not have a fixed melting or boiling point. Moreover, it shows the properties of its constituents. So, it must be a mixture. Sugar solution in water is a substance like X.
b. Substance Y has a fixed melting or boiling point but it cannot be split into simpler substances by chemical processes. Hence, it must be an element. Hydrogen is a substance like Y.
c. Substance Z is also a pure substance whose properties are entirely different from those of its constituents. Hence, it must be a compound. Sugar is a substance like Z.
d. Formation of Z (a compound) involves absorption or release of an appreciable amount of energy.
e. The three groups are metals, non-metals and metalloids. All the substances like Y are divided into these groups on the basis of their properties.
please mark me as the brainliest
Answer:
The temperature at which a substance's solid and liquid phases are in balance is known as the melting point. The temperature at which a substance's vapor pressure equals the pressure outside is known as its boiling point.
Explanation:
(a). There is no fixed melting or boiling point for substance X. In addition, it demonstrates the characteristics of its components. Thus, it must be a combination. A material like X is a sugar solution in water.
(b). Substance Y has a fixed melting or boiling point but cannot be broken down chemically into simpler chemicals. It must thus be an element. Like Y, hydrogen is a material.
(c). Substance Z is a pure substance that shares none of the characteristics of its components. It must thus be a combination. Z is a chemical similar to sugar.
(d). An considerable quantity of energy is absorbed during the formation of Z (a compound).
(e). Metals, non-metals, and metalloids make up the three groupings. These groupings are created based on the characteristics of all compounds similar to Y.
Hence, the answer to each question is explained above.
#SPJ3