A reddish brown metal X is added to solution metal nitrate Y.The metal present Y is used for making jewellary and turns black in air.Very thin foils of metal are used to decorate sweets.The compound Z formed on chemical reaction is blue in colour and metal present in Y is formed.Identify X Y & Z and write chemical reactions involved.
Answers
Answered by
29
The metal is copper (Cu).
The metal nitrate is Silver nitrate (AgNO3).
When silver nitrate reacts with copper, it becomes copper nitrate Cu(NO3)2
Cu + 2AgNO3→→→→Cu(NO3)2 + 2Ag
Therefore X = Cu
Y = AgN03
Z = Cu(NO3)2
Kindly, ask me if you have any doubts. If you are satisfied with my answer, don't forget to mark my answer as the brainliest answer.
Regards [Brainly Expert]
[Thank You]
The metal nitrate is Silver nitrate (AgNO3).
When silver nitrate reacts with copper, it becomes copper nitrate Cu(NO3)2
Cu + 2AgNO3→→→→Cu(NO3)2 + 2Ag
Therefore X = Cu
Y = AgN03
Z = Cu(NO3)2
Kindly, ask me if you have any doubts. If you are satisfied with my answer, don't forget to mark my answer as the brainliest answer.
Regards [Brainly Expert]
[Thank You]
Answered by
2
Answer:
Above answer is correct
Similar questions