A ray of light is incident normally on one of the face of a prism of angle 30 degree and refractive index root2. The angle of deviation will be......
A.)26 B.)0 C.)23 D.)15.
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student-name Jasmine asked in Science
A ray of light is incident normally on one face of prism of angle 30 and R.I.=root2. What will be the angle of deviation?
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student-name Nishant Agrawal answered this
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Refractive index = root 2 (given)
sin angle incidence/sine angle refraction = root 2
sin angle 90/sine angle r = root 2 (as ray is incident normally)
sine angle r = 1/root 2
sine angle 45 = 1/root 2
Angle r = 45 degree............1
Now, the sum of two interior opposite angles of a triangle is equal to its exterior angle.
In the case of prism,
Angle of deviation = angle of refraction,r1 + angle of refraction.r2
= 2 angle of refraction (As r1=r2)
= 2*45 (from 1)
= 90 degree.
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student-name Jasmine asked in Science
A ray of light is incident normally on one face of prism of angle 30 and R.I.=root2. What will be the angle of deviation?
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student-name Jasmine answered this
2 unhelpful votes in Science, Class X
that's not the answer
Was this answer helpful2
student-name Jasmine answered this
2 unhelpful votes in Science, Class X
that's not the answer
Was this answer helpful-6
student-name Nishant Agrawal answered this
107 helpful votes in Science, Class XII-Science
Refractive index = root 2 (given)
sin angle incidence/sine angle refraction = root 2
sin angle 90/sine angle r = root 2 (as ray is incident normally)
sine angle r = 1/root 2
sine angle 45 = 1/root 2
Angle r = 45 degree............1
Now, the sum of two interior opposite angles of a triangle is equal to its exterior angle.
In the case of prism,
Angle of deviation = angle of refraction,r1 + angle of refraction.r2
= 2 angle of refraction (As r1=r2)
= 2*45 (from 1)
= 90 degree.
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