A resistance of R ohms is connected in series with a parallel circuit comprising of two resistances 12 ohms and 8 ohms respectively. The total power dissipated in the circuit is 70 watts when applied voltage is 20 volts. Calculate the value of R.
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Power across 4Ohm= V244=36W
So, V4=12V
Since 4 and 6 Ohm are parallel, so
Req.=2.4 Ohm
As 4 and 6 Ohm are parallel, the voltage across them is same=12V. So, current through parallel circuit
I=122.4=5A
As this circuit is in series with R, so same current flows through R i.e, 5A.
Potential difference across R is (15–12)=3V as parallel branch has 12V and source is 15V.
So, R=15–125=0.6Ω
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