Question

A resistor is cut in two equal pieces and joined in parallel.what is the resistance in combination

Answer 1

Hi Mate !!


Q.A resistor is cut in two equal pieces and joined in parallel.what is the resistance in combination ?

solution :- Let us assume that the resistor have resistance as R .

When it is cut into two equal parts then the resistance also get halved as resistance is directly proportional to Length of the resistor.

New resistance ( resistance of each two resistor ) will be :- R/2

They are connected in parallel combination !

So, then using the formula of resistance in parallel combination :-



1/R° = 1/R1 + 1/R2

Where R° is resistance of the resistor in parallel combination !


1/R° = 1/(R/2) + 1/( R/2 )

1/R° = 2/R + 2/R


1/R° = 4/R

R ° = R/4

So, Resistance in parallel combination will be one fourth of the Resistance of the resistor.

$< hope \: this \: helps. >$

Answer 2

Answer:

Let the starting resistance is R ,now cut it in half in two peice now resistance is R/2 AND R/2. RIGHT

now come to parallel combination

1/Req = 1/r1 +1/r2

There for. 1/(r/2) +1/(r/2)

It will look like = 2/R+2/R = 4/R

Now R equivalent= R/4 so the answer Will be R/4

Thanks