Question

A resistor of 100 ohm ,pure inductance ofL=0.5H and capacitor are in series in a circuit containing an a.c. source of 220V and 50Hz .In the circuit current is ahead of the voltage by 30 degree . find the value of the capacitance .

Answer 1

The value of the capacitance is C = 1.46 F

Explanation:

In the circuits  

Inductive Reactance X2  =2πvL=2π(50)×(0.5)=50πΩ

Let capacitance be C so, xc  = 1/ 2πvc  = 1  /  100πc

Current leads voltage (circuit is more capacitive) by 30° = ϕ

tanϕ =   X  C  −X  L  / R

tan (30°) = 1/  100πc  B − 50π  /  100

That gives C = 1.46 F

Hence the value of the capacitance is C = 1.46 F

Also learn more

The equivalent resistance of circuit across points A and B is equal to

[A] 22.5 Ω

[B] 25 Ω

[C] 37.5 Ω

[D] 75 Ω

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