A rhombus of side 20cm has two angles of 60 each .Find the length of diafinals
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hello,
for this question we will use trignometry
inΔAOD
sin30°=AO/AD
1/2=AO/20
AO=10cm
∴diagonal AC=2AO=20cm
now
cos30°=OD/AD
√3/2=OD/20
OD=10√3cm
∴diagonal BD=2OD=20√3cm
hope this helps,if like it please mark it as brainliest
for this question we will use trignometry
inΔAOD
sin30°=AO/AD
1/2=AO/20
AO=10cm
∴diagonal AC=2AO=20cm
now
cos30°=OD/AD
√3/2=OD/20
OD=10√3cm
∴diagonal BD=2OD=20√3cm
hope this helps,if like it please mark it as brainliest
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Question :
A rhombus of side 20cm has two angles of 60 each .Find the length of diagonals.
Answer :
The length of diagonals are 20 cm and 20√3cm.
Given :
Side of rhombus = 20cm
Angles = 60° each
To find :
The length of diagonals
Solution :
In ΔAOD,
Sin 30° = AO/AD
=> 1/2 = AO/20
=> AO = 20 × 1/2
=> AO = 10cm
∴ Diagonal AC = 2AO =20cm
Now,
Cos 30° = OD/AD
=> √3/2 = OD/20
=> OD = 20 × √3/2
=> OD = 10√3cm
∴Diagonal BD = 2 OD = 2 × 10√3cm
= 20√3cm
Hence, the length of diagonals are 20 cm and 20√3cm.
#SPJ3
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