Question

A rifle weighting 5kgfires a 25g bullet with speed of 300ms^-1. The velocity of the rifle is Dont give unwanted answer. Answer only if you know.​

Answer 1

Answer:

Given : Mass of one bullet m=40 gm =0.04 kg

Velocity of bullet v=1200 ms

−1

Maximum exerted by man F=144 N

Let the total number of bullets fired per sec be n

Using F=∫Pdt ⟹F=PΔt

Thus this force balances the net linear momenta offered by the bullets in one sec.

∴ F=nmv

144=n(0.04)(1200) ⟹n=3 bullets per sec

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Answer 2

Answer:

hii

Explanation:

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