Question

A right angle triangle ABC with sides 3cm, 4cm, 5cm is revolved about the fixed side of 4cm. Find the volume and TSA.

Answer 1

h = 4cm
r = 3cm

V = π r² h/3
= 22/7 * 3 * 3 * 4/3
=37.41 cm³

TSA = πrl
=22/7 *3 * 5
=47.14 cm²

Answer 2

Answer:

The volume is  $37.7142 cm^3$ and total surface area is  $75.428 cm^2$

Step-by-step explanation:

We are given that A right angle triangle ABC with sides 3 cm, 4 cm, 5 cm is revolved about the fixed side of 4 cm

So, height of the cone so formed is 4 cm

Radius of the cone = 3 cm

Slant height = 5 cm

Volume of cone = $\frac{1}{3} \pi r^2 h$

                           = $\frac{1}{3} \times \frac{22}{7} \times 3^2  \times 4$

                           = $37.7142 cm^3$

Total surface area of cone = $\pi rl +\pi r^2$

                                            = $\frac{22}{7} \times 3 \times 5 + \frac{22}{7} \times 3^2$

                                            = $75.428 cm^2$

Hence the volume is  $37.7142 cm^3$ and total surface area is  $75.428 cm^2$