Question

A right angled triangle has the largest side as 13 cm and one of the sides containing the right angle as12 cm the its area in cmsquare is

Answer 1

Here, hypotenuse is 13 cm... One side is 12 & other side is 5 as
${13}^{2} = {12}^{2} + {5}^{2}$
$area = \frac{1}{2} \times 12 \times 5 = 30$
Area=30cm^2

Answer 2

Answer:

30 sq.cm.

Step-by-step explanation:

Hypotenuse = 13 cm

Perpendicular = 12 cm

To Find Base we will use Pythagorean theorem

$Hypotenuse^2=Perpendicular^2+Base^2$

$13^2=12^2+Base^2$

$169=144+Base^2$

$169-144=Base^2$

$25=Base^2$

$5=Base$

Area of triangle = $\frac{1}{2} \times Base \times Height$

                         = $\frac{1}{2} \times 5 \times 12$

                         = $30 cm^2$

Hence the area of the triangle is 30 sq.cm.